The major products of the following reaction | vedclass

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(B) The reaction proceeds in two main steps:$1$. Reimer-Tiemann reaction: $4$-chlorophenol reacts with $CHCl_3$ and aqueous $NaOH$ to form $5$-chloro$

Vedclass · Accepted Answer

$2-$hydroxy$-5-$chlorobenzyl alcohol and formic acid

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(B) The reaction proceeds in two main steps:$1$. Reimer-Tiemann reaction: $4$-chlorophenol reacts with $CHCl_3$ and aqueous $NaOH$ to form $5$-chloro$-2-$hydroxybenzaldehyde.$2$. Cannizzaro reaction: The aldehyde formed reacts with $HCHO$ and concentrated $NaOH$ (cross-Cannizzaro reaction). The aldehyde is reduced to the corresponding alcohol ($5$-chloro$-2-$hydroxybenzyl alcohol),and $HCHO$ is oxidized to sodium formate $(HCOONa)$.$3$. Acidification: Finally,treatment with $H_3O^+$ converts the phenoxide and formate salt into $5$-chloro$-2-$hydroxybenzyl alcohol and formic acid $(HCOOH)$.

The major products of the following reaction are:

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